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Marysya12 [62]
2 years ago
14

What is the value of x? Enter your answer in the box. X 8 2 X= 30° 452

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
6 0
X=50-digressed In Daren she neej
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What is the value of x in the equation 2<br> (4x+)-(3x+2)- 8(9-x) = x
Readme [11.4K]

Answer:

open the bracket

(4X+)-3X-2-72+X=X

4X+(-3X)-74+X=X

X-74+X=X

2X-74=X

then collect the term

-74=X-2X

-74=-X

divide by negative every side then you get

X=74

7 0
2 years ago
Find the ordered pair for the equation: y = 2x + 10 where x = 3
pogonyaev
IT IS 15 BECAUSE YOU HAVE TO ADD IT UP

8 0
3 years ago
Read 2 more answers
You draw one card from a? 52-card deck. then the card is replaced in the deck and the deck is? shuffled, and you draw again. fin
Solnce55 [7]

there are 4 tens in a deck so probability of picking a ten is 4/52 reduced to 1/13

 there are 13 clubs in a deck, probability for that is 13/52 reduced to 1/4

probability for both is 1/13 x 1/4 = 1/52

6 0
3 years ago
What is the area of the figure?
rewona [7]

Answer:

57 square feet

Step-by-step explanation:

Split the boxes into two parts.

One box measuring 11.5 ft long and 3 ft wide. (Box A)

The second box measuring 7.5 ft long and 3 ft wide. (Box B)

Area (figure) = Area of box A + Area of box B

Area of box A

3 × 11.5 = 34.5 ft²

Area of box B

3 × 7.5 = 22.5 ft²

Area of figure = 34.5 + 22.5

Area of figure = 57 ft²

3 0
3 years ago
Math again yay!...Ew math
Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
2 years ago
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