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In-s [12.5K]
3 years ago
14

Can someone tell me the answer to this question

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0
The answer is A I just took the quiz
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Someone smart help me please
wolverine [178]
(-5,2) concave up

Hope this helps :)
6 0
3 years ago
What is the equation of the line passing through the points (2/5, 19/20) and (1/3, 11/12) in slope-intercept form?
antiseptic1488 [7]

Answer: b is the answer

Step-by-step explanation:

4 0
2 years ago
Which circle is the graph of the equation (x + 4)2 + (y – 5)2 = 4?
garri49 [273]

Answer: CIRCLE C

Step-by-step explanation:

8 0
2 years ago
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
marissa [1.9K]

Complete question:

A circle with radius 3 has a sector with a central angle of 1/9 pi radians

what is the area of the sector?

Answer:

The area of the sector = \frac{\pi}{2} square units

Step-by-step explanation:

To find the area of the sector of a circle, let's use the formula:

A = \frac{1}{2} r^2 \theta

Where, A = area

r = radius = 3

\theta = \frac{1}{9}\pi

Substituting values in the formula, we have:

A = \frac{1}{2}*3^2* \frac{1}{9}\pi

A = \frac{1}{2}*9* \frac{1}{9}\pi

A = 4.5 * \frac{1}{9}\pi

A = \frac{\pi}{2}

The area of the sector = \frac{\pi}{2} square units

8 0
3 years ago
1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues
kondor19780726 [428]
1. Let s_n be the number of seats in the n-th row. The number seats in the n-th row relative to the number of seats in the (n-1)-th row is given by the recursive rule

s_n=s_{n-1}+5


Since s_1=21, we have

s_2=s_1+5
s_3=s_2+5=s_1+2\cdot5
s_4=s_3+5=s_1+3\cdot5
\cdots
s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5

So the explicit rule for the sequence s_n is

s_n=21+5(n-1)\implies s_n=5n+16

In the 15th row, the number of seats is


s_{15}=5(15)+16=91

2. Let p_n be the amount of profit in the n-th year. If the profits increase by 6% each year, we would have

p_2=p_1+0.06p_1=1.06p_1
p_3=1.06p_2=1.06^2p_1
p_4=1.06p_3=1.06^3p_1
\cdots
p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1

with p_1=40,000.

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of


p_{20}=1.06^{19}\cdot40,000\approx121,024

3. Now let p_n denote the number of pushups done in the n-th week. Since 3\cdot4=12, 12\cdot4=48, and 48\cdot4=192, it looks like we can expect the number of pushups to quadruple per week. So,

p_n=4p_{n-1}

starting with p_1=3.

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3
6 0
3 years ago
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