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Fynjy0 [20]
2 years ago
10

Given the function

Mathematics
1 answer:
Setler79 [48]2 years ago
5 0

lim \: f(x) = ( \infty  + 4)( \infty  - 2) {}^{2}  \\ x -  >  \infty

lim \: f(x) =  \infty  \times  \infty   \\ x -  >  \infty

lim  \: f(x)=  \infty \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  =  \frac{x(1 -  \frac{4}{x})(x - 2) {}^{2}  }{x}  \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  = (1)( \infty  - 2) {}^{2}  \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  =  \infty \\ x -  >  \infty

We can then say that the function f(x)=(x-4)(x-2)² admits an asymptotic direction parallel to the y-axis at +∞ and -∞ as well since we have to follow the same steps.

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ArbitrLikvidat [17]

Given data:

The first equation is 3j +14=-5z.

The second equation is -10j=5z​ .

Add both the equations.

\begin{gathered} (3j+14)+(-10j)=-5z+5z \\ -7j+14=0 \\ 7j=14 \\ j=2 \end{gathered}

Substitute 2 for j in the first equation.

\begin{gathered} 3(2)+14=-5z \\ 20=-5z \\ z=-4 \end{gathered}

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The measure of angle A to the nearest tenth of a degree is: A 18.5 B 19.5 C 20.5
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Answer:

B


Step-by-step explanation:

<u>This is a right triangle as shown by the right angle.</u>

  • The side opposite the right angle is the hypotenuse, which is 9.
  • The side opposite angle A is 3.

So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

sin\theta=\frac{opposite}{hypotenuse}

Since, we need angle A, \theta is A, opposite side is 3, and hypotenuse is 9, we substitute:

sinA=\frac{3}{9}\\sinA=\frac{1}{3}

<em>To solve for the angle, we use our calculator and find the inverse sin of \frac{1}{3} :</em>

A=sin^{-1}(\frac{1}{3})\\A=19.47

<em>Rounding to nearest tenth of a degree:</em>

A=19.5

B is the right choice.

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It’s domain

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Step-by-step explanation:

I got it right on a test

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