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Fynjy0 [20]
2 years ago
10

Given the function

Mathematics
1 answer:
Setler79 [48]2 years ago
5 0

lim \: f(x) = ( \infty  + 4)( \infty  - 2) {}^{2}  \\ x -  >  \infty

lim \: f(x) =  \infty  \times  \infty   \\ x -  >  \infty

lim  \: f(x)=  \infty \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  =  \frac{x(1 -  \frac{4}{x})(x - 2) {}^{2}  }{x}  \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  = (1)( \infty  - 2) {}^{2}  \\ x -  >  \infty

lim \:  \frac{f(x)}{x}  =  \infty \\ x -  >  \infty

We can then say that the function f(x)=(x-4)(x-2)² admits an asymptotic direction parallel to the y-axis at +∞ and -∞ as well since we have to follow the same steps.

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