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1 year ago

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Who was Karl Pearson?

2 answers:

solmaris [256]1 year ago

4 0

Answer:

Biostatistics is, as the name suggests, the application of statistical analysis to the topic of biology, including the creation of experiments and the gathering of biological data. It is a relatively new field, having been created in the 19th and 20th centuries, but as a combination of two different fields it has been very successful as a technique and thus has been widely adopted.

Step-by-step explanation:

Ulleksa [173]1 year ago

3 0

Answer:

Karl Pearson was a British statistician, leading founder of the modern field of statistics, prominent proponent of eugenics, and influential interpreter of the philosophy and social role of science.

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Which statement is FALSE?

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In the diagram, R, S, and T are all points of tangency. What is the perimeter of Triangle<br> XYZ?

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Answer:

54 cm

Step-by-step explanation:

Perimeter = TZ + TX + RX + RY + SY + SZ

TZ = 5 cm

TX = 13 cm

RY = 9 cm

RX = TX = 13 cm (tangents drawn from and external point)

SY = RY = 9 cm (tangents drawn from and external point)

SZ = TZ = 5 cm (tangents drawn from and external point)

Plug in the values:

Perimeter = 5 + 13 + 13 + 9 + 9 + 5 = 54 cm

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2 years ago

Locate√3 on number line and jusitify

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2 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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2 years ago