The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
According to the given question.
We have an equation

So, to find the resulting equation of the above equation we need to simplify.
First we will take LCD



Multiply both the sides by x.

Again multiply both the sides by x



Factorize the above equation
⇒3x(x+6)+2(x+6) = 0
⇒(3x + 2)(x+6) = 0
⇒ x = -2/3 or x = -6
Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
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Answer: 9
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Answer:
Without graphing, determine whether the parabola -2(3x + 5)(6 - x) opens up or down and ... Use the shortcut to write the equation for the axis of symmetry and find the ...
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