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2 years ago

when doing a complex presentation which of the fallowing will be the best tool to begin designing your presentation

Computers and Technology

2 answers:

qaws [65]2 years ago

7 0

but where are the option bro

algol132 years ago

7 0

Answer:

Explanation:

The options are:

a) Open Office Writer

b) Open Office Impress

c) an outline

d) photographs

The most commonly used presentation software is Microsoft PowerPoint but it is not always available; as is the case here. Of the options, Open Office Impress is the closest in its functions to PowerPoint and is a good tool to design a complex presentation.

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An online survey is an effective way for an administrative professional to gather information. True False

Strike441 [17]

Answer:

True is the correct answer for the above question.

Explanation:

An online survey is done with the help of social sites that connects many people in conversation from all over the world. So to do an effective survey, it is best to choose the online medium.
The administrative professional is a professional, who works to do administrative tasks like managing the organization.
The above question-statement says that the online survey is the best survey, which is the correct statement, which is described above. Hence the answer is true for the above question.

7 0

3 years ago

What's the component of the hardware?

melisa1 [442]

Some component of the hardware are central processing unit (CPU), monitor, mouse, keyboard, computer data storage, graphics card, sound card, speakers and motherboard.

I’m sure theirs more but here’s so. Hope this helps!

7 0

3 years ago

Read 2 more answers

Write a program that asks the user to enter a student's name and 8 numeric tests scores (out of 100 for each test). The name wil

sergeinik [125]

Answer:

// program in Python

# function to find grade

def grade(t_score):

#grade A

if t_score >=90:

return 'A'

#grade B

elif t_score >=80 and t_score <90:

return 'B'

#grade C

elif t_score >=70 and t_score <80:

return 'C'

#grade D

elif t_score >=60 and t_score <70:

return 'D'

#grade F

else:

return 'F'

# function to find average score

def calc_average(test_score):

#variable to find sum

total = 0

for i in range(len(test_score)):

#calculate total score

total = total + test_score[i]

# find average

return total/float(len(test_score))

#array to store score

test_score = []

#read name of student

name = input("Enter student's name: ")

for i in range(8):

#read score

t_score = int(input("Enter the score {}: ".format(i+1)))

#add score to array

test_score.append(t_score)

#call function to find Average

averageScore = calc_average(test_score)

#print name of Student

print("Student Name: ", name)

#print each Score

for i in range(len(test_score)):

#print each Score and Grade

print("Score: ",test_score[i], "Letter Grade: ",grade(test_score[i]))

# print Average Score

print("Average Score: ", averageScore)

Explanation:

Read name of student from user.Then read 8 test scores from user. Call the function grade() to find the grade of a test score.Call the function calc_average() to find the average score of all test.Print each score and corresponding grade and print average score.

Output:

Enter student's name: Sam

Enter the score 1: 45

Enter the score 2: 98

Enter the score 3: 67

Enter the score 4: 86

Enter the score 5: 60

Enter the score 6: 77

Enter the score 7: 92

Enter the score 8: 32

Student Name: Sam

Score: 45 Letter Grade: F

Score: 98 Letter Grade: A

Score: 67 Letter Grade: D

Score: 86 Letter Grade: B

Score: 60 Letter Grade: D

Score: 77 Letter Grade: C

Score: 92 Letter Grade: A

Score: 32 Letter Grade: F

Average Score: 69.625

3 0

3 years ago

A device that is connected to a network that is identified by a unique number and works as an individual part of the network is

VMariaS [17]

Cellular phone? I'm pretty sure

7 0

3 years ago

Prompt the user for data points. Data points must be in this format: string, int. Store the information before the comma into a

stiks02 [169]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

ArrayList<String> Strs = new ArrayList<String>(); ArrayList<Integer> Ints = new ArrayList<Integer>();

String datapoint;

System.out.print("Data point (0 to quit): ");

datapoint = input.nextLine();

while(!"0".equals(datapoint)){

System.out.println("Data point: "+datapoint);

String[] datapointSplit = datapoint.split(", ");

Strs.add(datapointSplit[0]);

Ints.add(Integer.parseInt(datapointSplit[1]));

System.out.print("Data point (0 to quit): ");

datapoint = input.nextLine(); }

System.out.println("Strings: "+Strs);

System.out.println("Integers: "+Ints);

}}

Explanation:

In Java:

Declare string and integer array lists

ArrayList<String> Strs = new ArrayList<String>(); ArrayList<Integer> Ints = new ArrayList<Integer>();

Declare datapoint as string

String datapoint;

Prompt the user for data point (An entry of 0 ends the program)

System.out.print("Data point (0 to quit): ");

Get the data point

datapoint = input.nextLine();

This is repeated until an entry of 0 is entered

while(!"0".equals(datapoint)){

This prints the datapoint

System.out.println("Data point: "+datapoint);

This splits the datapoint to 2

String[] datapointSplit = datapoint.split(", ");

This adds the string part to the string array list

Strs.add(datapointSplit[0]);

This adds the integer part to the integer array list

Ints.add(Integer.parseInt(datapointSplit[1]));

Prompt the user for another entry

<em> System.out.print("Data point (0 to quit): ");</em>

<em> datapoint = input.nextLine(); } </em>

Print the string entries

System.out.println("Strings: "+Strs);

Print the integer entries

System.out.println("Integers: "+Ints);

8 0

3 years ago