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1 year ago

Y by the power of 2 + 4=20

Mathematics

2 answers:

LenaWriter [7]1 year ago

8 0

Answer:

y is equal to 4 if that's what ur asking for

Karo-lina-s [1.5K]1 year ago

8 0

Answer:

16 if ur asking for y^2+4=20

Step-by-step explanation:

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pentagon [3]

Answer:

plot points at (0,4),(3,1),(5,7),(8,5)

Step-by-step explanation:

hope this helps (:

7 0

2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago

The line graph shows the number of goals scored

Neporo4naja [7]

Answer:

a) 1 game

b) 41 goals

c) median = 2

Step-by-step explanation:

As we can see in the line graph, where we have the 0 for the number of goals scored, the graph indicates only 1 in the number of games, so we have only 1 game where no goals were scored.

To find the total number of goals scored, we multiply the goals scored by the number of games for that score, and then sum them all:

total goals = 1*0 + 4*1 + 5*2 + 6*3 + 1*4 + 1*5 = 41 goals

To find the median, we put all the goals in crescent order, and then find the value in the middle. As we have 18 games, the middle value will be an average of the 9th and 10th terms.

We have 1 number 0, 4 numbers 1 and 5 numbers 2 in the beginning, so for these 10 numbers, the 9th and the 10th are the score 2, so the median is 2.

8 0

2 years ago

Please answer! (1) what mistake was made? (2) what suggestion could help avoid that?

AveGali [126]

Answer:

1) the signs of the numbers is not in standard form

2) always make sure that the signs of the two equations is standarised and then solve

please follow me

3 0

2 years ago

The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude is 6 m. Find the total surface area of

Eva8 [605]

Answer:

806.12 m

Step-by-step explanation:

Step 1: Write the data

Side (s) = 12

Altitude (h) = 6

Step 2: Write the formula for surface area of right hexagonal pyramid

Area = 3√3/2*s² + 3*s*√(h²+3s²/4)

Step 3: Substitute values of 's' and 'h'

Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]

Area = 806.12 m

Therefore, the total surface area of the pyramid is 806.12 m.

4 0

2 years ago