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vodomira [7]
2 years ago
5

PLEASE SOLVE PRETTY URGENT

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
5 0

If the two cylinders are similar, that means that the ratio between the diameter and the height will be the same in both solids.

In the bottom cylinder, we have a ratio of 3ft to 12ft. This is a ratio of 3:12, or 1:4, where the 1 is the height and 4 is the diameter.

The top cylinder has a height of 8 inches, meaning that the 8 corresponds to the 1 in the ratio. Thus, we can set up the equation like this:

\frac{1}{4} =\frac{8}{x}

To get from 1 to 8, we have to multiply by 8. But because we don't want to change the ratio, we have to multiply the denominator by 8 as well:

\frac{1}{4}*\frac{8}{8}=\frac{8}{32}

That means the top cylinder has a diameter of 32. But we can't forget our units. Because we used 8 <em>inches</em> in our ratio, that means the diameter is <u>32 inches</u>.

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If RS = 3x + 1, ST = 2x – 2, and RT = 64, find the value of x.
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S+ST = RT  

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3 years ago
A committee must be formed with 4 teachers and 5 students. If there are 11 teachers
Ivenika [448]

Answer:

11C4 × 11C5

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What is the average of 1.90 7.99 4.33 5.21?
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7 0
3 years ago
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The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle
Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

|AB|=\sqrt{(-1--5)^2+(8-6)^2}

|AB|=\sqrt{16+4}

|AB|=\sqrt{20}

The length of AD is

|AD|=\sqrt{(-1--5)^2+(6-4)^2}

|AD|=\sqrt{16+4}

|AD|=\sqrt{20}

The length of BC is:

|BC|=\sqrt{(-1-3)^2+(8-6)^2}

|BC|=\sqrt{16+4}

|BC|=\sqrt{20}

The length of CD is

|CD|=\sqrt{(-1-3)^2+(6-4)^2}

|CD|=\sqrt{16+4}

|CD|=\sqrt{20}

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB=\frac{8-6}{-1--5}=\frac{1}{2}

Slope of BC =\frac{8-6}{-1-3}=-\frac{1}{2}

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be  a square. It is a rhombus

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