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erica [24]
3 years ago
5

If RS = 3x + 1, ST = 2x – 2, and RT = 64, find the value of x.

Mathematics
1 answer:
Mrac [35]3 years ago
4 0

S+ST = RT  

3x+1 + 2x-2 = 64  

5x = 65  

x = 13

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Zeroes:

We must solve

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t^2-45t+324=0

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Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

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Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

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3 years ago
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x= 1/3  and y=−6

Step-by-step explanation:

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Answer:

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