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2 years ago

If RV=w and SU=w–30, what is the value of w?

Mathematics

1 answer:

DIA [1.3K]2 years ago

5 0

Answer:

w = 60

Step-by-step explanation:

the midsegment SU is half the measure of side RV, then

SU = RV , so

w - 30 = w ( multiply through by 2 to clear the fraction )

2w - 60 = w ( subtract w from both sides )

w - 60 = 0 ( add 60 to both sides )

w = 60

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Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the

love history [14]

Answer:

attached below

Step-by-step explanation:

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3 years ago

1. What is the slope of the line that passes through the points E(3, 0) and F (6, -3)?

Mama L [17]

Answer:

1. m=- -1 2. -1+1

Step-by-step explanation:

Ok for the first one you need to label 3 x1 0 y1 6 x2

and -3 y2

Next you need to do y2-y1 over x2-x1 so fill that in and your equasion is (-3-0)

------------ = -3

( 6-3) ----

That reduces to -1 because -3 divided by 3 is -1

As for number 2 we need to find b to do this pick any of the y's from before we can go with 0 so the 0 is y in the equasion and we already learned slope is -1 so your equasion should be 0=--1+b ok to solve this you need to add -1 to both sides since its a negitive so you add 1 to 0 which is 1 and when you add 1 to -1 it cancells it out so you have 1=b so b is 1 for the equsion you just fill it in so it is y=- -1+1

I hope I helped

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3 years ago

write a possible point slope form of the equation of the line that passes through the points (4,4) and (3,-2)?

Mashutka [201]

m=-2-4/3-4=-6/-1=6

y-4=6(x-4)

y=6x-20

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2 years ago

What is the sum of ? I will put a pic if the answer is correct ill mark brainlist

olga2289 [7]

$\text{The sum of } 1\frac{7}{10} \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}$

Solution:

Given that we have to find the sum of $1\frac{7}{10} \text{ and } 3\frac{3}{5}$

Let us first convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

Therefore,

$1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}$

Now we can add both the fractions

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}$

Make the denominators same

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}$

Now convert the fraction to mixed number

When we divide 53 by 10 , the remainder is 3

Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

$\frac{53}{10} = 5\frac{3}{10}$

Thus the sum of given mixed fraction is $5\frac{3}{10}$

6 0

2 years ago

Drew jumped farther than all 4 students above but jumped shorter than 7 feet , 7 inches. How far could drew have jumped? Write s

S_A_V [24]

<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.</h3>

Step-by-step explanation:

Here, the needed table is attached for the reference.

Now, as we can see from the table:

The distance covered by Cindy = 2 yards, 1 foot 3 inches

The distance covered by Tyrette = 7 feet, 2 inches

The distance covered by Nina = 2 yards, 1 foot, 1 inch

The distance covered by Monique = 7 feet, 4 inches

As we know : 1 yard = 3 feet

So, the distance covered by :

Cindy = 2 yards, 1 foot 3 inches = 3 ft x (2) + 1 ft + 3 in = 7 ft 3 in

Tyrette = 7 feet, 2 inches

Nina = 2 yards, 1 foot, 1 inch = = 3 ft x (2) + 1 ft + 1 in = 7 ft 1 in

Monique = 7 feet, 4 inches

So by comparing all distances, we can see that:

The maximum distances jumped by all four is 7 ft 4 inches.

The distance covered by Drew is less than 7 ft 7 in.

So, he must have jumped 7 ft 5 inches OR 7 ft 6 inches.

Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.

4 0

3 years ago