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CaHeK987 [17]
2 years ago
10

A circle is centered on point B. Points A, C and D lie on its circumference.

Mathematics
2 answers:
Delvig [45]2 years ago
5 0

Answer:

what idk im so dumb but it will help

QveST [7]2 years ago
4 0

Answer:

23 degrees

Step-by-step explanation:

If <ADC is the arc measure of the circle, by definition the center angle (<ABC) has the same measure as its intercepted arc.

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Find the unit rates: 8 ounces for $0.89? 32 ounces for $2.39?
Lilit [14]

Answer:

.89/8=.11

2.39/32=.07

Step-by-step explanation:

.89/8=.11

2.39/32=.07

6 0
2 years ago
Please help meee! :&lt; An author receives $0.60 for each hardcover book or paperback book that is sold. There were x hardcover
rusak2 [61]
D) 47,000

0.60 (<em>x</em>+38,000)= 51,000
(0.60<em>x</em>)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000
5 0
3 years ago
&lt;&gt;&lt;&gt;&lt;&gt;&lt;&gt;Simple true and false math&lt;&gt;&lt;&gt;&lt;&gt;&lt;&gt;
skad [1K]

Answer:

true

Step-by-step explanation:

just my opinion but for me it's true

7 0
2 years ago
Calculate the average rate of change of f(x) = 1 x - x2 - 2 for 3 ≤ x ≤ 6. A) -163 18 B) -18 163 C) 163 18 D) 18 163
larisa86 [58]
To solve this we are going to use the average rate of change formula: A(x)= \frac{f(b)-f(a)}{b-a}
where
A(x) is the average rate of change of the function
f(a) is the position function evaluated at a
f(b) is the position function evaluated at b
a is the first point in the interval
b is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so a=3 and b=6. Lets replace those values in our formula:
A(x)= \frac{f(b)-f(a)}{b-a}
A(x)= \frac{f(6)-f(3)}{6-3}
A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}
A(x)= \frac{-32-(-8)}{3}
A(x)= \frac{-32+8}{3}
A(x)= \frac{-24}{3}
A(x)=-8

We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
3 0
3 years ago
Read 2 more answers
The sum of 3 consecutive number multiples of 6 is 162 find thesse numbers
MAXImum [283]

let the numbers are x , x+1 ,x+2

∴ 6 [ x + (x+1) +(x+2) ] = 162

∴ x + (x+1) + (x+2) = 162/6 = 27

∴3x + 3 = 27

∴ 3x = 27 - 3 = 24

∴ x = 24/3 = 8

<u>So, the numbers are 8 , 9 , 10</u>

7 0
3 years ago
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