Question

In the following figure, the square ABCD is inscribed in the circle centered at point P. What is the area of the circle?

Answer 1

Answer:

$A_{Circle} \approx 39.24\: units^2$

Step-by-step explanation:

Square ABCD is inscribed in a circle with center P such that BC = 5 units.

BD will be diagonal of the square as well as diameter of the circle.

$BD = BC\times\sqrt 2$

$\implies BD = 5\sqrt 2$

-> Diameter of the circle $(d) = 5\sqrt 2$

-> Radius of the circle $(r) = 2.5\sqrt 2=3.535\: units$

$A_{Circle} =\pi(r)^2$

$\implies A_{Circle} =3.14(3.535)^2$

$\implies A_{Circle} =3.14(3.535)^2$

$\implies A_{Circle} =39.2381465$

$\implies A_{Circle} \approx 39.24\: units^2$