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patriot [66]
3 years ago
12

A team is being formed that includes eight different people. There are eight different positions on the teams. How many differen

t ways are there to assign the right people to the eight ​positions
Mathematics
1 answer:
abruzzese [7]3 years ago
6 0

Answer:

40320 different ways

Step-by-step explanation:

That problem is a permutation one

We have eight people to occupy  one position in a team, without any constraint at all

So

Total number of events   = P(8)

P (8)  =  8!

P (8)  =  8*7*6*5*4*3*2*1

P (8)  =  40320 different ways

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How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
3 years ago
3 a. It takes Adriana 20 minutes to walk 5 blocks to the library. Complete the table of equivalent ratios to show Adriana’s two
Dafna11 [192]

Answer:

It takes 4 minutes per block and she can walk 12.5 blocks in 45 minutes.

Step-by-step explanation:

20 / 5 = 4 minutes per block

20 + 20 + 5 = 45

5 + 5 + 2.5 = 12.5

Hope this helps, I did the test last year.

6 0
2 years ago
A milk carton is 20cm long, 5cm wide and 40cm high. What volume of milk can it hold (in cubic cm)? *​
Marina CMI [18]

Answer:

30 times 10 is 300. 300 times 50 is 15,000.

Step-by-step explanation:

bc i know

6 0
3 years ago
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Delmar is constructing an equilateral triangle. He uses his straightedge to draw a segment and labels the endpoints W and X. Wit
MakcuM [25]
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral. Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
7 0
3 years ago
FIRST RIGHT ANSWER GETS BRAINLIEST!!!!
nikklg [1K]
I dont know how to write this on my phone but its 1500<, except the arrow has the line under it to represent at least.
8 0
2 years ago
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