Select the correct answer from each drop-down menu.

Mathematics

1 answer:

DENIUS [597]2 years ago

5 0

The expression that the question is referring to is not visible. Sorry, I couldn’t give you a more valid answer.

You might be interested in

Which of the diagrams correctly displays a→+b→=c→, using the parallelogram method?

adoni [48]

Answer:It’s. B

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Can i have some help

Andrews [41]

Answer: g(x) = 3/2 x + 9

Step-by-step explanation:

h(x) = -2/3 x - 1

perpendicular lines always have the opposite sign, reciprocal slope

so, the slope of the perpendicular line would be: m = 3/2

y = mx + b

y = 3/2 x + b

plug in (-4, 3) to find b

3 = 3/2 (-4) + b

3 = -6 + b

b = 9

y = 3/2 x + 9

g(x) = 3/2 x + 9

5 0

3 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$