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bekas [8.4K]
2 years ago
14

164 hundreds - 12 hundreds

Mathematics
2 answers:
andrezito [222]2 years ago
7 0

Answer:

1.52

Hope this helps :)

Step-by-step explanation:

step one:

put them as decimals which would be 1.64 and 0.12

step two:

subtract which would be 1.64 - 0.12

step three:

solve your answer would be 1.52 or 152 hundredths

nalin [4]2 years ago
6 0

Answer:

152 hundred

Step-by-step explanation:

164 hundred - 12 hundred = 152 hundred

Please rate!

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Answer:

A) Particular solution:

2x+\frac{1}{2}e^{-x}-\frac{8}{5}

B) Homogeneous solution:

y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))

C) The most general solution is

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

Step-by-step explanation:

Given non homogeneous ODE is

y''+4y'+5y=10x+e^{-x}---(1)

To find homogeneous solution:

D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)

To find particular solution:

y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\

Substituting y_{p},y'_{p},y''_{p} in (1)

y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\

Equating the coefficients

5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\

The general solution is

y=y_{h}+y_{p}

from (2) ad (3)

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

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Answer:

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Step-by-step explanation:

Given:

Revenue means the sales or turnover of a company when it sells its products. In other words, it is nothing but the income of a company on selling the products.

Here, the company is selling backpacks. So, revenue is the amount earned by the company on selling 'x' backpacks. The linear model to represent the same is given below.

The revenue received from selling 'x' backpacks is given as:

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Now, in order to find the revenue received on selling 40 backpacks, we need to plug in 40 for 'x' in the equation above and solve for the revenue, 'R'.

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