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2 years ago

Pls give me the full answer

Mathematics

1 answer:

nikdorinn [45]2 years ago

7 0

All of the Questions are solved on the images shown below. These images are from Microsoft Whiteboard that I created.

<h2>I'm in sixth grade, and don't know how to answer 2 and 5. So I'm only going to answer questions 1, 3 and 4. </h2>

really sorry about that

1. Answer = 90m²

3. Answer = 50in²

4. Answer = 108cm²

yup, this is how weird i am

I took the screen shot of answer 3 before 1 lol!

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so sorry I couldn't help on all problems

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Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra

stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A = $\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate =1.01

7 0

3 years ago

James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo

Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is $y = 2 ^n$

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒ n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒ for n = 1 , y = 2 ..... (1)

Similarly, if the paper if folded TWICE ⇒ n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒ for n = 2 , y = 4 ..... (2)

⇒ $y = 2^2 = 2^n$

Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7

So, $y = 2^ n = 2^7 = 128$

⇒ There are total 128 equal parts.

Lastly, if the paper is folded ELEVEN times ⇒ n = 11

So, $y = 2^ n = 2^{11} = 2048$

⇒ There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is $y = 2 ^n$

8 0

4 years ago

Question 16..........

Elanso [62]

Since the diameter is 6 cm, the radius is 3 cm. Use the area formula to get 113.04 cm squared. Then, you multiply that by the height of the rod, which is 20 cm. The volume of one rod is 2260.8 cm cubed. To find how much steel is needed for 189 rods, multiple the volume of one rod by 189. Your answer should be 427291.2 cm³.

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4 years ago

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On Monday, the theater club sells 14 tickets for the school play. On Tuesday, they sell 10 tickets. On those two days, they sell

Margarita [4]

Answer:

<h2>31 tickets</h2>

Step-by-step explanation:

Step one:

number of tickets sold

monday=14

tuesday=10

the number of tickets sold for Monday and Tuesday combined is

14+10= 24

step two:

we want to find how many tickets make 30%

so 30/100*24

0.3*24

=7.2 tickets,

Approximately 7 ticket

Therefore the total ticket is

14+10+7

=31 tickets

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3 years ago

HELP PLSS (NO LINKS)

inysia [295]

61/8 or 7 and 5/8. I would try either one

5 0

3 years ago

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