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3 years ago

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics

2 answers:

jeka943 years ago

4 0

Answer:

Step-by-step explanation:

$(-3,-3) =(x_1,y_1)\\ (-6,1)=(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}\\ \\d = \sqrt{(-6-(-3))^2+(1-(-3))^2}\\ \\d = \sqrt{(-6+3)^2+(1+3)^2}\\ \\d = \sqrt{(-3)^2 +(4)^2}\\ \\d = \sqrt{9+16}\\ \\d = \sqrt{25}\\ \\d =5$

Law Incorporation [45]3 years ago

3 0

(9,4) ...........................

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Help me pls! Thnx if u do ✨✌️

daser333 [38]

Neither of them are correct. When you plug in both of the fractions into the equation, you get answers like 2/9 (from plugging in 1/3) and 1/9 (from plugging in 1/6). None of them are equal to 9.

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3 years ago

In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j

bonufazy [111]

Answer:

The Ranking Percentile is (B) 97.5%

Explanation :

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score= $\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}$

Substituting the values in the above equation, we find

Z-score= $\frac{(694-490)}{102}$ =2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

3 0

3 years ago

Nick had 3 1/4 bottles of water for his wrestling practice. When he finished he had 1 2/4 bottles of water left. He said he used

sweet-ann [11.9K]

1 2/4+2 1/4 ≠ 3 1/4 but 1 2/4+2 1/4 = 3 3/4

7 0

3 years ago

Consider the figure. What is JL?

lisov135 [29]

The answer for the above mentioned problem is JL = 12.5

Step by step explanation:

Given:

JM = 8

KM = 6

To Find:

JL = ?

Formula to be used:

$KM^2$ = JM x ML

In order to find " JL" we must first find "ML",

$KM^2$ = JM x ML

$6^2$ = 8 x ML

36 = 8 x ML

36/8 = ML

ML = 4.5

Now JL = 4.5+8

= 12.5

Thus the value of JL = 12.5

3 0

3 years ago

Which quadratic function has a leading coefficient of 2 and a constant term of –3?

Romashka [77]

The answer is f(x) = 2x2 + 3x – 3

f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

We are looking for a = 2, c = -3

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: f(x) = –3x2 – 3x + 2
a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3

6 0

3 years ago

Read 2 more answers