HELP ASAP! I NEED 5b ONLY!!!

Mathematics

2 answers:

kipiarov [429]3 years ago

5 0

Answer:

You want to find the treasure shown on the map. To get to the treasure, start at 1% and move to 100%. The only way you can move on the map is if a number is greater than the number you are currently on.

Step-by-step explanation:

Brilliant_brown [7]3 years ago

4 0

Answer : the piece near the middle can be located on 30 spots at the end of 2 turns, so 30/32
0.9375%
explanation : the piece can move anywhere depending on where it moves the first turn. the only place it can’t go is on the places where other pieces are currently on.

[ this is what i think ]

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.