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just olya [345]
4 years ago
5

60 pOINTS HELP PLEASE 4. A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5

m/s.
Circle one: KE / GPE / both

Show your work for finding the values of each type of energy the object has:
Mathematics
1 answer:
Solnce55 [7]4 years ago
6 0
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
ke = 0.5 \times 20 \times  {5}^{2}  \\ ke = 10 \times 25 \\ ke = 250 \: joules
gpe = 20 \times 9.81 \times 2 \\ gpe = 40 \times 9.81 \\ gpe = 392.4 \: joules
g is taken as 9.81
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The wall in the family room is exactly 12feet long. Your couch is ten feet and 6 inches long. Once the couch is placed, how much
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Answer:

1 foot and 6 inches

Step-by-step explanation:

12 feet (144 inches) - 10 feet and 6 inches (126 inches) = 1 foot and 6 inches (18 inches)

7 0
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Name a set of vertical angles in the image below:
melomori [17]
<h3>Answer:  B) 1 & 3</h3>

Explanation:

Vertical angles form when we have an X shape like this. They are opposite one another and always congruent. Angles 2 and 4 is the other set of vertical angles.

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The equation y = 36 + 18x models the relationship
wariber [46]

Answer:

Option B) The height, in inches, of a typical apple tree

Step-by-step explanation:

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y ---> the height in inches, of a typical golden  delicious apple tree

we have

y=36+18x

Remember that

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8 0
4 years ago
HELP QUICK LIKE RIGHT NOW!please
pogonyaev

Answer:

1/2 = 1/2

Step-by-step explanation:

5/10 is equal to 1/2 and 1/2 cant get smaller making you answer 1/2 = 1/2

8 0
3 years ago
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The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
3 years ago
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