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Naily [24]
2 years ago
6

The graph of g(x) is shown. Determine the transformations from the parent function f(x)=x2 to the new function g(x)=15x2+5

Mathematics
1 answer:
Viktor [21]2 years ago
7 0

Answer:

The graph of g is translated down 5 units from the graph of f and stretched horizontally

Step-by-step explanation:

was correct on test :)

pls brainliest XD

.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.

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Chris sells books for a commission of $2.60 per book and $50 a month. His salary is determined by the function M=2.60 b+50, wher
Thepotemich [5.8K]
<span>M=2.60b + 50

When b = 25

M = 2.60(25) + 50 = $115

Answer: Chris earns $115 for selling the 25 books.</span>
3 0
4 years ago
29 = v+17 what the answer cs ion get it
Alexus [3.1K]

Answer:

12

Step-by-step explanation:

29 = v + 17

29 - 17 = v

12 = v

6 0
2 years ago
Your medical research team is investigating the standard deviation of the cost of a 30-day-supply of a certain heart medication.
Valentin [98]

Considering the situation described, the hypothesis tested are given as follows:

  • The null hypothesis is H_0: \sigma \geq 23
  • The alternative hypothesis is H_1: \sigma < 23

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the standard deviation is not less than $23, that is:

H_0: \sigma \geq 23

At the alternative hypothesis, it is tested if there is significant evidence t conclude that the standard deviation is less than $23, that is:

H_1: \sigma < 23

More can be learned about an hypothesis test at brainly.com/question/26454209

4 0
3 years ago
Prove that<br>1/1+root 2 + 1/root2 + root3 + 1/root3 + root4 + 1/root8 +root9 = 2​
daser333 [38]

Step-by-step explanation:

LHS:

\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\ldots \ldots \ldots \ldots \ldots+\frac{1}{\sqrt{8}+\sqrt{9}}1+21+2+31+3+41+……………+8+91

Rationalizing the denominator, we get

\Rightarrow\left(\frac{1}{1+\sqrt{2}} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}\right)+\left(\frac{1}{\sqrt{2}+\sqrt{3}} \times \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}}\right)+\left(\frac{1}{\sqrt{3}+\sqrt{4}} \times \frac{\sqrt{3}-\sqrt{4}}{\sqrt{3}-\sqrt{4}}\right)+\cdots \ldots+\left(\frac{1}{\sqrt{8}+\sqrt{9}} \times \frac{\sqrt{8}-\sqrt{9}}{\sqrt{8}-\sqrt{9}}\right)⇒(1+21×1−21−2)+(2+31×2−32−3)+(3+41×3−43−4)+⋯…+(8+91×8−98−9)

We know that,

\left(a^{2}-b^{2}\right)=(a+b)(a-b)(a2−b2)=(a+b)(a−b)

Now, on substituting the formula, we get,

=\frac{1-\sqrt{2}}{1-2}+\frac{\sqrt{2}-\sqrt{3}}{2-3}+\frac{\sqrt{3}-\sqrt{4}}{3-4}+\cdots \ldots \cdot \frac{(\sqrt{8}-\sqrt{9})}{8-9}=1−21−2+2−32−3+3−43−4+⋯…⋅8−9(8−9)

\Rightarrow \frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\cdots+\frac{1}{\sqrt{8}+\sqrt{9}}=(\sqrt{2}-1)+(\sqrt{3}-\sqrt{2})+(\sqrt{4}-\sqrt{3})+\cdots+(\sqrt{9}-\sqrt{8})⇒1+21+

4 0
3 years ago
Eight minus a number divided by three is greater than or equal to eleven
AfilCa [17]

Answer:

Step-by-step explanation:

8-x/3>=11 is the equation, and the answer is:

x<= -9, so any number less than -9 is correct.

5 0
3 years ago
Read 2 more answers
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