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gtnhenbr [62]
2 years ago
10

Jack has a rectangular piece of land, the area of which is represented by a1 = 9.5l. His brother has a different rectangular pie

ce of land, the area of which is represented by a2 = l(14 − l). Let a represent the area in square meters and l represent the length in meters of the pieces of land. The two equations plotted on a graph meet at a point as shown in the image.
The area of the brothers’ pieces of land will be the same when the length is ______ meters.

Mathematics
2 answers:
Orlov [11]2 years ago
3 0

Answer:2

Step-by-step explanation:

SVEN [57.7K]2 years ago
3 0

Answer: 13

Step-by-step explanation:

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Solve for x. 5x−2(x+1)=1/4 ​ Enter your answer in the box. x =
horsena [70]

x =(-4-√96)/40=(-1-√ 6 )/10= -0.345

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8 0
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Solve the linear equation.
Akimi4 [234]

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8 0
3 years ago
Help me find the slope to these points<br> (2,5) and (8, -4)
ale4655 [162]

Answer:

slope = -3/2

Step-by-step explanation:

The slope of a line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1/x2−x1.

We have that x1=2, y1=5, x2=8, y2=−4.

Plug the given values into the formula for slope: m= (-4)-(5)/ (8)-(2) = -9/6 = -3/2

the slope of the line is m = -3/2

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2 years ago
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jasenka [17]

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7 0
2 years ago
The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

5 0
2 years ago
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