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iris [78.8K]
3 years ago
5

The steps to get the answer​

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

1.7 - 1.5 = 1.2

11.2 - 3.1 = 8.1

Step-by-step explanation:

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5f - 45

Step-by-step explanation:

(f-9)(5)

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5f-45

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11) Determine if the following numbers are<br> prime, composite or neither.<br> 13
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13 is Prime

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3 years ago
The area of a quadrilateral is 64 in^2. The length of the quadrilateral is 32 in. How wide is the quadrilateral?
Mars2501 [29]

Answer: 2 inches

Explanation: The area formula is length times width (L*w=a). We know that the area is 64in^2 (a=64) and the length is 32in (L=32), so we put those values into the equation and get 32*w=64. We then get w by itself by dividing both sides by 32, and get w=2. so the width is 2 inches.

7 0
3 years ago
1. Identify the focus and the directrix for 36(y+9) = (x - 5)^2 2. Identify the focus and the directrix for 20(x-8) = (y + 3)^2
Simora [160]

Problem 1

Focus: (5, 0)

Directrix:  y = -18

------------------

Explanation:

The given equation can be written as 4*9(y-(-9)) = (x-5)^2

Then compare this to the form 4p(y-k) = (x-h)^2

We see that p = 9. This is the focal distance. It is the distance from the vertex to the focus along the axis of symmetry. The vertex here is (h,k) = (5,-9)

We'll start at the vertex (5,-9) and move upward 9 units to get to (5,0) which is where the focus is situated. Why did we move up? Because the original equation can be written into the form y = a(x-h)^2 + k, and it turns out that a = 1/36 in this case, which is a positive value. When 'a' is positive, the focus is above the vertex (to allow the parabola to open upward)

The directrix is the horizontal line perpendicular to the axis of symmetry. We will start at (5,-9) and move 9 units down (opposite direction as before) to arrive at y = -18 as the directrix. Note how the point (5,-18) is on this horizontal line.

================================================

Problem 2

Focus:  (13,-3)

Directrix:  x = 3

------------------

Explanation:

We'll use a similar idea as in problem 1. However, this time the parabola opens to the right (rather than up) because we are squaring the y term this time.

20(x-8) = (y+3)^2 is the same as 4*5(x-8) = (y-(-3))^2

It is in the form 4p(x-h) = (y-k)^2

vertex = (h,k) = (8,-3)

focal length = p = 5

Start at the vertex and move 5 units to the right to arrive at (13,-3). This is the location of the focus.

Go back to the focus and move 5 units to the left to arrive at (3,-3). Then draw a vertical line through this point to generate the directrix line x = 3

5 0
3 years ago
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