Answer:
x=-3
Step-by-step explanation:
2
−
1
⋅
1
2
=
6
2-1 \cdot \frac{12}{x}=6
2−1⋅x12=6
Solve
1
Combine multiplied terms into a single fraction
2
−
1
⋅
1
2
=
6
2
+
−
1
⋅
1
2
=
6
2
Multiply the numbers
2
+
−
1
⋅
1
2
=
6
2
+
−
1
2
=
6
3
Subtract
2
2
2
from both sides of the equation
2
+
−
1
2
=
6
2
+
−
1
2
−
2
=
6
−
2
4
Simplify
Subtract the numbers
Subtract the numbers
−
1
2
=
4
5
Multiply all terms by the same value to eliminate fraction denominators
−
1
2
=
4
⋅
−
1
2
=
⋅
4
6
Simplify
Cancel multiplied terms that are in the denominator
Re-order terms so constants are on the left
−
1
2
=
⋅
4
-12=x \cdot 4
−12=x⋅4
−
1
2
=
4
-12=4x
−12=4x
−
1
2
=
4
7
Divide both sides of the equation by the same term
−
1
2
=
4
−
1
2
4
=
4
4
8
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left
=
−
3
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Solution
=
−
3
Answer:
100
Step-by-step explanation:
5^2=25 25*4=100
Answer:
I don't understand what this is
Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.
