We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.
The probability of a data score between two z-scores is given by formula
.
Using above formula, we will get:

Now we will use normal distribution table to find probability corresponding to both z-scores as:


Now we will convert
into percentage as:

Upon rounding to nearest tenth of percent, we will get:

Therefore, our required probability is 27.4% and option C is the correct choice.
Answer
x = 3981071.7055
y = 3981.0717
x > y
Step by step explanation
First let's find the value of x and y by taking anti - log.
log X = 6.6
X = log^ -1 (6.6)
X = 3981071.7055
Similarly,
log Y = 3.6
Y = log ^(-1) 3.6
Y = 3981.0717
Once we found the values of X and Y , we can easily compare them.
Here x > y
Hope you will understand the concept.
Thank you. :)
Answer:
.66
Step-by-step explanation:
cmon bro how do u not know this
4 divide 6
.66666666666666666666666666666666666
Answer:
D=-12 CDE=130
Step-by-step explanation: