Answer -3.5 reason is because if u do 7 multiplied by 1/2 u get that answer
Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in
in the expression
, that's the answer for linear equations and limits.
So we have:
![9x-3\\9(8)-3\\72-3\\69](https://tex.z-dn.net/?f=9x-3%5C%5C9%288%29-3%5C%5C72-3%5C%5C69)
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value
into the simplified expression to get the correct answer. Shown below:
![\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%2B8x-9%7D%7Bx%5E2-1%7D%5C%5C%5Cfrac%7B%28x%2B9%29%28x-1%29%7D%7B%28x-1%29%28x%2B1%29%7D%5C%5C%5Cfrac%7Bx%2B9%7D%7Bx%2B1%7D)
<em>Now putting 1 in
gives us the limit:</em>
![\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B9%7D%7Bx%2B1%7D%5C%5C%5Cfrac%7B1%2B9%7D%7B1%2B1%7D%3D%5Cfrac%7B10%7D%7B2%7D%3D5)
So the answer is 5
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
On Oct 11: 1INR=0.04976AED
Oct 27 1INR=0.05022AED
However It's Price was highest on Oct 9 when 1AED was equal to 20.2395 INR