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Leokris [45]
3 years ago
6

Help pls tysm in advance

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

\bold{\huge{\underline{ Solution }}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • We have given some information in the above table

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • We have to find the mean, median and mode of the given data.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>For </u><u>completion </u><u>of </u><u>table </u><u>you </u><u>should </u><u>know </u><u>the </u><u>basics </u><u>formulas </u><u>:</u><u>-</u>

  • For calculating x( mid point)

\sf{=}{\sf{\dfrac{Sum \:of\: class \:interval }{ 2}}}

<u>That </u><u>is</u><u>, </u>

\sf{=}{\sf{\dfrac{ = 18 + 25}{2}}}

\sf{=}{\sf{\dfrac{ = 43}{2}}}

\sf{= 21.5 }

[ For more calculation ,Please refer the attachment ]

  • For calculating fx
  • Multiply frequency and midpoint

\sf{ fx = frequency {\times} midpoint }

\sf{ fx = 8 {\times} 21.5 }

\sf{ fx = 172 }

[ For more calculation please refer the attachment ]

<h3><u>Now</u><u>, </u></h3>

We have to calculate mean, median and mode of the given data

<h3><u>For </u><u>mean </u></h3>

We know that the,

Mean = Sum of all observation / no. of observation

<u>That </u><u>is </u>

\sf{ Mean = }{\sf{\dfrac{ {\sigma}fx}{{\sigma}x}}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ Mean = }{\sf{\dfrac{ 1811 }{ 187.5}}}

\sf{ Mean = 9.65}

Hence, The mean of the given data is 9.65

<h3><u>For </u><u>Median </u></h3>

<u>We </u><u>know </u><u>that</u><u>,</u><u> </u><u>For </u><u>odd </u><u>numbers </u>

\sf{ Median = l + }{\sf{\dfrac{ (n/2 - c)}{ f}}}{\sf{ h }}

<u>Here, </u>

\sf{ n  = }{\sf{\dfrac{ 50 + 1}{ 2}}}

\sf{ n = }{\sf{\dfrac{ 50 }{ 2}}}

\sf{  n = 25 }

  • Lower limit = 34
  • c = 20
  • f = 14
  • h = 41 - 34 = 7

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u><u>:</u><u>-</u>

\sf{ Median = 34 + }{\sf{\dfrac{ (25-20)}{ 14}}}{\sf{ 7 }}

\sf{ = 34 + }{\sf{\dfrac{ 5}{ 14}}}{\sf{ {\times}7 }}

\sf{  = 34 + }{\sf{\dfrac{ 35}{ 14}}}

\sf{ = 34 + 2.5}

\sf{ = 36.5 }

Hence, The median of the given data is 36.5 .

<h3><u>For </u><u>Mode </u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

\sf{ M=  l }{\sf{\dfrac{ (f1 - fo)}{ 2f1 - fo - f2 }}}{\sf{ {\times} h }}

  • lower limit = 34
  • f1 = 14
  • fo = 12
  • f2 = 12
  • H = 7

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ M=  34 }{\sf{\dfrac{ (14 - 12)}{ 2(14)- 12 - 12 }}}{\sf{ {\times} 7 }}

\sf{ M= 34{\times}}{\sf{\dfrac{ 2}{ 28 - 24 }}}{\sf{ {\times} 7 }}

\sf{ M= 34{\times}}{\sf{\dfrac{ 2}{ 4 }}}{\sf{ {\times} 7 }}

\sf{ M= 34{\times}}{\sf{\dfrac{ 1}{ 2 }}}{\sf{ {\times} 7 }}

\sf{ M= 34{\times}}{\sf{\dfrac{ 7}{ 2 }}}

\sf{ M= 34 + 3.5 }

\sf{ M= 37.5 }

<u>So</u><u>, </u>

  • Mode = 37.5

Hence ,The mode of the given data is 37.5 .

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