X=number of gallons that she must order.
4 gallons-----------------3 weeks
(7 gallons + x)--------12 weeks
We solve this rule of 3.
(7 gallons +x)3 weeks=4 gallons*12 weeks
21 gallons weeks+3 x weeks=48 gallons weeks
3x weeks=48 gallons weeks - 21 gallons weeks
3x weeks=27 gallons weeks
x=(27 gallons weeks) / 3 weeks=9 gallons.
Solution: she must order 9 gallons more.
Answer:
option 3
Step-by-step explanation:
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
Answer:
k=m/5
Step-by-step explanation:
explained in the attached pi
All we need to do is to divide August and September rainfall measurements into two equal halves and then substract 0.6 from one of them and add 0.6 to the other one.
6.2 ÷ 2 = 3.1
3.1 - 0.6 = 2.5
3.1 + 0.6 = 3.7
It's said that in August there was 0.6 inch more rainfall, so the bigger value (3.7 inches) is for August and the smaller value (2.5 inches) is for September.
