Factor the following:
2 x^3 + x^2 - 18 x - 9
Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)
Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)
x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)
Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):
Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
What is the interquartile range of this data set? 2,5,9,11,18,30,42,55,58,73,81
Tcecarenko [31]
Answer:
I think it's 49 I'm sry if I'm wrong hope you luck
Step-by-step explanation:
Answer:
The distance between them after 30 minutes is 6.5 km.
Step-by-step explanation:
Speed = 
Sarah's speed = 6 km/hr = 1.6667 m/s
Emily's speed = 10 km/hr = 2.7778 m/s
The measure of angle between their bearings = 
After 30 minutes (1800 seconds);
distance = speed x time
Sarah would have covered a distance = 1.6667 x 1800
= 3000 m
= 3 km
Emily would have covered a distance = 2.7778 x 1800
= 5000 m
= 5 km
The distance between them, a, can be determined by applying the cosine rule;
= 
+ 
- 2bcCos A
= 
+ 
-2(5000 x 3000) Cos 105
= + -2(5000 x 3000) x (-0.2588)
= 2.5 x 
+ 9 x 
+ 7764000
= 41764000
a = 
= 6462.5073
a = 6462.5 m
The distance between them after 30 minutes is 6.5 km.
Answer:
hi
Step-by-step explanation:
the function is c(x) = 31 + 0.18*x
where $31 is a fixed cost, and $0.18 is the cost per mile drive (where the number of miles driven)
So the fixed cost, $31, is the cost per day of rent (this price does not depend on the number x), and the linear cost, $0.18, is the cost per mile driven (because this number is multiplied by x in the function), then the right answer is B: "$31 is the cost per day to rent the car and $0.18 is the cost per mile."
Answer:
i think its 6c+240=1200
Step-by-step explanation:
6 = amount of nights
240=tax
c = total cost a night
1200 = budget
