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3 years ago

15

Gcf of 63 and 27 i will give toy 12pts

1 answer:

NeTakaya3 years ago

4 0

GCF is 3×3 so it is 9

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Ellen can purchase 5 apples for $1.75. How many apples can she get for $1?

Romashka-Z-Leto [24]

Answer:

2 apples

Step-by-step explanation:

1.75 ÷ 5 = 0.35
1 ÷ 0.35 = 2.85
2.85 rounded = 2

I hope this helps!

6 0

2 years ago

A shirt was reduced in price by 20% during a sale. If the shirt was bought

yaroslaw [1]

£57.6 bc it is extremely cool and correct

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2 years ago

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Find the zeros (roots) of the following equations. f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0

Talja [164]

Hi,
$f(1)=2*1^5-9*1^4+12*1^3-12*1^2+10*1-3\\
=2-9+12-12+10-3\\
=0\\

f(x)=(x-1)(2x^4-7x^3+5x^2-7x+3)\\


g(x)=2x^4-7x^3+5x^2-7x+3\\

g(3)=2*3^4-7*3^3+5*3^2-7*3+3\\
=162-189+45-21+3\\
=0\\

g(x)=(x-3)(2x^3-x^2+2x-1)\\

h(x)=2x^3-x^2+2x-1\\

h( \dfrac{1}{2} )=2* \dfrac{1}{8} - \dfrac{1} {4}+1-1\\
=0\\

h(x)=(2x-1)(x^2+1)\\


f(x)=(x-1)(x-3)(2x-1)(x+i)(x-i)\\


$
Roots are 1,3,0.5,i,-i.

8 0

3 years ago

A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?

slavikrds [6]

Answer:

$P(Woman) = \frac{23}{106}$

Step-by-step explanation:

Given

$Women = 23$

$Men = 83$

Required

$P(Woman)$

This is calculated as the number of women divided by the population of the class

i.e.

$P(Woman) = \frac{Women}{Women + Men}$

So, we have:

$P(Woman) = \frac{23}{23+83}$

$P(Woman) = \frac{23}{106}$

7 0

2 years ago

Mia spends 45 min reading each day. She does 2/5 of her reading at school. How many minutes does Mia spend reading at school?

Cerrena [4.2K]

Mia spends 18 minutes reading at school.

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3 years ago

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