Answer: 1.284M NH3
Explanation: (12.23 grams)/(17.0 gramms/mole) = 0.7191 moles
Dissolved in 560.0 ml (=0.5600L)
(0.7191 moles)/(0.560L) = 1.284M (4 sig figs)
Answer:
In 0.7 liters (700 ml) there are 122, 85 grams of NaCl
Explanation:
We calculate the weight of 1 mol of NaCl:
Weight 1 mol NaCl= Weight Na + Weight Cl= 23+35,5 g= 58,5g/mol
1 mol NaCl-------58,5 g
3mol NaCl -------x= (3mol NaClx58,5 g)/1 mol= 175, 5 g
3M (175,5 g in this case)---> 3 moles in 1 L of solution
1 L-----175,5 g NaCl
0,7L--x= (0,7Lx175,5 g NaCl)/1L =122,85 g NaCl
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