<u>Answer:</u> The volume when the pressure and temperature has changed is 1332.53 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K](https://tex.z-dn.net/?f=P_1%3D0.950atm%5C%5CV_1%3D200L%5C%5CT_1%3D27%5EoC%3D%5B273%2B27%5DK%3D300K%5C%5CP_2%3D0.125atm%5C%5CV_2%3D%3FL%5C%5CT_2%3D-10%5EoC%3D%5B273-10%5DK%3D263K)
Putting values in above equation, we get:
Hence, the volume when the pressure and temperature has changed is 1332.53 L
I believe the answer is A. 40 mL
Answer:
32.4 L
Explanation:
Note 1:
The Standard Temperature and Pressure (STP) is defined by IUPAC as air at 0 gradius Celcius and 1 bar.
Note 2:
The Ideal Gas Law is used for solving this problem.
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Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
