2 years ago

Help!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

yaroslaw [1]2 years ago

6 0

<h2>Answer:</h2><h2>x=3 </h2><h2>p=3csc (β)sec(θ)</h2><h2>hope this helps! ;)</h2>

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Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

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$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
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3 years ago

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Step-by-step explanation:

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3 years ago

I need both of these questions answered I also HATE links so please don’t put any down(;´༎ຶٹ༎ຶ`)

Mademuasel [1]

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