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2 years ago

(science) 18 point! i'll give 5 star,1 thank who do all of this question THANK YOU!!!

Biology

1 answer:

charle [14.2K]2 years ago

5 0

Answer:

gravitational

sun 274m/s²

mecury - 3.7 m/s²

earth - 9.807 m/s²

Mars -3.721m/s²

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In eukaryotes, extranuclear inheritance occurs when genetic information is transmitted by mechanisms other than through nuclear

Vlad [161]

Answer:

- cpDNA organization is more similar to that of prokaryotes than eukaryotes

- chloroplast chromosomes contain genes that are involved in photophosphorylation

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4 years ago

Imagine that a area of the crust became weak so that melted rocks move up to the surface

Rama09 [41]

If this were the case that magma would harden into rock therefore creating new crust

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3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

The calculated  $X^2$  exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. 

4 0

3 years ago

Hershey and Chase used a DNA-based virus for their work. How might the results have been different if they had used an RNA virus

4vir4ik [10]

Answer:

The correct answer is c.With an RNA virus, radioactive RNA would have been in the final pellet.

Explanation:

Hershey and Chase infected E.coil with bacteriophage which was having DNA as its genetic material. The bacteriophage was labeled with radioactive sulfur and radioactive phosphorus and it was radioactive phosphorus that was found in the bacterial cells or pellet.

As because DNA contains phosphorus, not protein therefore they it was proved that DNA is the genetic material. Similarly, RNA is also a nucleic acid which is genetic material for many viruses and contains phosphorus.

So if Hershey and chase might have chosen an RNA virus then radioactive RNA would have been present in the pellet. So the correct answer is c.

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3 years ago

Contrast How is faciliated diffusion diffrent from active transport

Mazyrski [523]

Answer:

Explanation:

Whereas facilitated diffusion is a passive process and does not require energy. Active transport uses carrier proteins

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3 years ago