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denis-greek [22]
2 years ago
15

How many different outcomes are possible when three coins are flipped at the same time?​

Mathematics
2 answers:
liberstina [14]2 years ago
7 0

Answer:

8

Step-by-step explanation:

Mice21 [21]2 years ago
5 0

Answer:

<u>8</u>

Step-by-step explanation:

Now consider an experiment of tossing three coins simultaneously. The possible outcomes will be HHH, TTT, HTT, THT, TTH, THH, HTH, HHT. So the total number of outcomes is 23 = <u>8</u>.

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FIND THE VALUE OF X AND Y.(ordered pairs)<br><br>(x+y,0)=(8,x-y)​
Aliun [14]

Step-by-step explanation:

We know that...

x+y (from the first pair) corresponds to 8(in the second pair)..

0 (from the first pair) corresponds to x-y (in the second pair)..

Hence,

x + y = 8 \\ x - y = 0

By simply adding the two equations we get,

2x = 8 \\ x  = 4

Hence,

By substituting x=4, we get that y=4

Hence,

x=y=4

5 0
3 years ago
Which is less -2.34 or -2.2?
lidiya [134]

Answer:

-2.34

Step-by-step explanation:

It is further away from 0

8 0
2 years ago
Read 2 more answers
A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th
pochemuha

Answer:

x^2 + 15x - 60 = 0

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

(x + 15)\ by\ x

Area = 60in^2

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

Area = Length * Width

60= (x + 15) * x

Open Bracket

60= x^2 + 15x

Subtract 60 from both sides

x^2 + 15x - 60 = 0

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where

a = 1

b = 15

c = -60

So:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}

x = \frac{-15 \± \sqrt{225 + 240}}{2}

x = \frac{-15 \± \sqrt{465}}{2}

x = \frac{-15 \± \21.56}{2}

Split:

x = \frac{-15 + 21.56}{2} or x = \frac{-15 - 21.56}{2}

x = \frac{6.56}{2} or x = \frac{-36.36}{2}

x = 3.28 or x = -18.18

But length can't be negative;

So:

x = 3.28

The actual dimensions: (x + 15)\ by\ x is

Length =3.28 +15

Length =18.28

Width = x

Width =3.28

<em>The actual dimension is 18.28 by 3.28</em>

3 0
3 years ago
What is the surface area of the box? use your answer to problem 2 to write an equation
sammy [17]

Answer:

S=2lw+2lh+2wh

Step-by-step explanation:

If we consider the structure of a box with length l, width w, and height h, we may note that it is formed from six rectangular faces. The bottom and top faces are rectangles with sides of length l and w. Two of the side faces have side lengths l and h. And the remaining two side faces have side lengths w and h.

As the area of a rectangle is the product of its side lengths, we can put this together to get the surface area S of the box as

S=2lw+2lh+2wh

8 0
3 years ago
Please help I'll rate brainiest answer and 5 stars I suck at math
Leviafan [203]
The answer would be D

3 0
3 years ago
Read 2 more answers
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