Step-by-step explanation:
1. difference in algebraic expression is known SUBTRACTION
a² -b²=(a+b)(a-b)
see on "a" there is square and also on b
2. no there is no matter
now let multiply (a+b) (a-b)
a²+ab-ab-b²
a²-b²
now let multiply (a-b) (a+b)
a²+ab-ba-b²
ab and ba is same
a² -b²
The quadratic formula is:
(-b ± √b² - 4ac)/2a
So first we need to find what a, b, and c are by making the equation equal to 0.
We can do this by adding 13x and subtracting 10 to get -7x² + 13x - 10, so your values would be a = -7, b = 13, and c = -10.
Now you can just substitute them into the equation:
(-13 ± √13² - 4 × -7 × -10)/-14
I believe that is your answer in standard form, so I hope this helps!
9 to the 6th power + 5 to the 5th power+ 4 to the 4th power + 0 to the 3rd power + 0 to the 2nd power+ 0 to the 1s power.
18.56, 18.57, 18.58 or 18.59?