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Marianna [84]
2 years ago
9

You spin the spinner once.

Mathematics
1 answer:
MAVERICK [17]2 years ago
3 0

Answer:

50%

Step-by-step explanation:

The P(even or divisor of 28) = P(even) + P(divisor of 28) - P(even and divisor of 28). The P(even) = 2/4 = 1/2. The P(divisor of 28) = 2/4 = 1/2. The P(even and divisor of 28) = 2/4 = 1/2 as 2,4 are even numbers and divisors of 28.

1/2 + 1/2 - 1/2 = 1/2 = 50%

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Dr. Jane is studying the growing population of a species of jellyfish in a body of water. Each year, she records the population
olya-2409 [2.1K]

Answer:

983040

Step-by-step explanation:

Second Year : 15x4=60

Third Year : 60x4=240

Fourth Year : 240x4=960

Fifth Year : 960x4=3840

Sixth Year : 3840x4=15360

Seventh Year : 15360x4 = 61440

Eighth Year: 61440x4=245760

Ninth Year : 245760x4= 983040

4 0
3 years ago
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Solve: x ÷ 0.6 = 8.9<br><br><br> 5.34<br><br><br> 9.5<br><br><br> 8.3<br><br><br> 0.07
Basile [38]

Answer: x = 0.6 ÷ 8.9 = 5.34

Step-by-step explanation:

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2 years ago
Y/20=x <br> I need help on how to solve and the answer!
Deffense [45]

Answer:

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Step-by-step explanation:

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3 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
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Zina [86]

Answer:

The answer is 4. The line passes through the point (10,4).

Step-by-step explanation:

7 0
3 years ago
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