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astraxan [27]
2 years ago
11

If a tennis ball has a diameter of 14, What is the volume of the tennis ball? Round to the nearest hundreth Use

Mathematics
2 answers:
g100num [7]2 years ago
7 0

Answer:

1436.76... units^3

Step-by-step explanation:

Recall the formula for the volume of a sphere.

V = \frac{4}{3} \pi r^3

The question gives you diameter. As you know, diameter is twice the radius. Therefore, to convert diameter into radius, you divide the diameter by 2.

r = 14/2 = 7

Now that you have the radius, all you need to do is plug it into the volume formula.

V = \frac{4}{3}\pi 7^3 = 1436.76... units^3

vladimir2022 [97]2 years ago
3 0

if its diameter is 14, then its radius is half that or 7.

\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7 \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (7)^3}{3}\implies V=\cfrac{1372\pi }{3} \\\\\\ \stackrel{using~\pi =3.14}{V\approx 1436.03} \end{array}

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Answer:

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Step-by-step explanation:

Step  1  :

Solving a Single Variable Equation :

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Divide both sides of the equation by 29:

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Answer:

The solution of the given system of equations is,

x=\frac{b^2+ac}{a^2+b};\; y=\frac{ab-c}{a^2+b}

Step-by-step explanation:

The given equations are :

<em>x</em> + a<em>y</em> = b          .......(1)

a<em>x</em> - b<em>y</em> = c        .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable  and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

   <em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em>          ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

  a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

\implies y=\frac{ab-c}{a^{2}+b}

Now, substituting the above value of '<em>y</em>' in equation (3), we get

x=b-a(\frac{ab-c}{a^2+b})

\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}

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Hence, the solution of the given system of equations is,

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