For each equation how many solutions why?<br> Question e

A company has 8 mechanics and 6 electricians. If an employee is selected at random, what is the probability that they are an ele

Andre45 [30]

Answer:

$Probability = \frac{3}{7}$

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

$Total = n(Electrician) + n(Mechanic)$

$Total = 6 + 8$

$Total = 14$

Next, is to determine the required probability using the following formula;

$Probability = \frac{n(Electrician)}{Total}$

$Probability = \frac{6}{14}$

Divide numerator and denominator by 2

$Probability = \frac{3}{7}$

<em>Hence, the probability of selecting an electrician is 3/7</em>

4 0

3 years ago

48 logs on 6 trucks

blagie [28]

Answer:

288 is your answer. 8 is your answer.

Step-by-step explanation:

If you want to know how many logs all together, all you do is multiply.

48 x 6 = 288

288 is your answer.

Or division it is

48/6 = 8

8 is your answer.

6 0

3 years ago

The percent equivalent of 1.07 is ______ and the fraction equivalent is ______

lawyer [7]

1.07 as a percent is 107% 1.07 as a fraction is 1 1/14

Hope this helps!

6 0

3 years ago

Read 2 more answers

Last week you worked 7 hours more than you normally do. Your typical week totals 36 hours.What was the total number of hours you

sergejj [24]

The answer is 43 because 36 + 7 = 43

4 0

3 years ago

Read 2 more answers

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago

For each equation how many solutions why? Question e