All categories

2 years ago

For each equation how many solutions why? Question e

Mathematics

1 answer:

Kay [80]2 years ago

4 0

Answer:

one real solution

Step-by-step explanation:

it has only one solution since it is a linear graph and only intercepts the x axis once

You might be interested in

Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.

Georgia [21]

Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

$z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\ \\ 
z-score =2.326$

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.

5 0

3 years ago

The temperature when Spencer arrived at school was a very chilly

nekit [7.7K]

9 degrees. -4 + 13= 9.

6 0

2 years ago

Match the following proofs to each other. The answers there I guessed on but most likely not right. I need help. My grade is not

DanielleElmas [232]

Step-by-step explanation:

6 0

2 years ago

Using a white-board with graph paper or graphing technology such as Geogebra be able to perform a reflection for a pre-image ove

Marta_Voda [28]

Explanation:

The line of reflection is the perpendicular bisector of the segment joining a point with its reflected image.

___

The segment joining a point with its reflection is as short as possible consistent with the requirement that the reflected point be the same distance from the line that the original is. That means it is perpendicular to the line of reflection. Since the distance from that line is the same on either side, the line of reflection bisects the joining segment.

7 0

2 years ago

Find the missing sides using special right triangles

ANTONII [103]

Answer:

The answers are;

m = 9, e = 9

Step-by-step explanation:

The question relates to right triangles with special properties;

The given parameters of the given right triangles are;

The measure of an interior angle of the triangle = 45°

The length of the given leg length of the triangle = (9·√2)/2

The length of the other leg length of the triangle = n

The length of the hypotenuse side = m

A right triangle with one of the measures of the interior angles equal to 45° is a special triangle that has both leg lengths of the triangle equal

Therefore;

The length of the other leg of the right triangle = n = The length of the given leg of the triangle = (9·√2)/2

∴ n = (9·√2)/2

n = (e·√f)/g

Therefore, by comparison, we have;

e = 9, f = 2, and g = 2

By Pythagoras's theorem, we have;

m = √(n² + ((9×√2)/2)² = √((9×√2)/2)² + ((9×√2)/2)²) = √(81/2 + 81/2) = √81 = 9

m = 9.

5 0

2 years ago