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Nesterboy [21]
4 years ago
15

The percent equivalent of 1.07 is ______ and the fraction equivalent is ______

Mathematics
2 answers:
torisob [31]4 years ago
7 0
The percent is 10.7%.
lawyer [7]4 years ago
6 0
1.07 as a percent is 107% 1.07 as a fraction is 1 1/14

Hope this helps!
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Im really bad at these questions I need an answer and an explanation
Sophie [7]

Answer:

63/100 or 63%

Step-by-step explanation:

7 0
3 years ago
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algol13

Answer: The pre-image moves horizontally left.

The pre-image moved horizontally 3 units.

The pre-image moved vertically up.

The pre-image moved vertically 2 units.

Step-by-step explanation:

8 0
3 years ago
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Please help! Will give brainliest!:)
Mrrafil [7]

Answer:

Ex1: If $1000 is invested now with simple interest of 8% per year. Find the new amount after two years. P = $1000, t = 2 years, r = 0.08.

Step-by-step explanation:

hope this helps

8 0
3 years ago
Plzz help me solve questions 15 and 16...!!
iVinArrow [24]

15.

We have right triangles, with the ladder the hypotenuse of both and the wall the opposite side of both.

Call the ladder length <em>h.</em>

Against the wall we have the opposite of alpha the taller one:

q = h \sin \alpha - h \sin \beta

On the ground adjacent to beta is the longer one

p = h \cos \beta - h \cos \alpha

Dividing

\dfrac p q = \dfrac{  h \cos \beta - h \cos \alpha }{h \sin \alpha - h \sin \beta} =  \dfrac{ \cos \beta -\cos \alpha }{\sin \alpha - \sin \beta} \quad\checkmark

16.

Again I'm too lazy to draw the figure but you should.

Let's call <em>y </em>the height of the tower and <em>x</em> the distance from the observation point on the ground to the base of the tower.

\tan 60^\circ = \dfrac y x

\tan 30^\circ = \dfrac{y - 40}{x}

Since \sin 30 =\cos 60 = \frac 1 2 \textrm{ and } \cos 30 = \sin 60 = \sqrt{3}/2

\tan 60^\circ = \sqrt{3} = y/x

\tan 30^\circ = 1/\sqrt{3} = (y-40)/x

Dividing,

\sqrt{3}/ (1/\sqrt{3}) = (y/x) / ((y-40)/x)

3 = y/(y-40)

3y - 120 = y

2y = 120

y = 60

x = y/\sqrt{3} = 60(\sqrt{3}/3) = 20 \sqrt{3}

Answer: Height 60 meters, distance 20√3 meters

5 0
3 years ago
Find a power series for the function, centered at c. f(x) = 1 9 − x , c = 4 f(x) = [infinity] n = 0 Incorrect: Your answer is in
Wewaii [24]

Looks like the given function is

f(x)=\dfrac1{9-x}

Recall that for |<em>x</em>| < 1, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

We want the series to be centered around x=4, so first we rearrange <em>f(x)</em> :

\dfrac1{9-x}=\dfrac1{5-(x-4)}=\dfrac15\dfrac1{1-\frac{x-4}5}

Then

\dfrac1{9-x}=\displaystyle\frac15\sum_{n=0}^\infty\left(\frac{x-4}5\right)^n

which converges for |(<em>x</em> - 4)/5| < 1, or -1 < <em>x</em> < 9.

4 0
4 years ago
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