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2 years ago

How do you do this? Because I don’t get it

Mathematics

2 answers:

olganol [36]2 years ago

6 0

Multiply by -1 each time to get the answer in the output

Savatey [412]2 years ago

6 0

Answer:

5,-17

6,-21

Step-by-step explanation:

When the input goes up by 1 the output goes up by negative 4 each time

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2. A bakery makes 40 different flavors of muffins. 25% of the flavors have chocolate as

oksano4ka [1.4K]

Answer:

2. 10 muffins with chocolate 30 without chocolate

Step-by-step explanation:

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3 years ago

Determine the approximate value of side a.

Nostrana [21]

The answer to this question is 97 i think

6 0

3 years ago

You owe your mom 10$. You pay her back 7$. Write an expression that can be used to represent this situation.

mezya [45]

Answer:

10$-7$=3$

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Simplify 5 - (-1)<br> O -6<br> O -4<br> O 6<br> 0 4

makvit [3.9K]

The equation simplified is 6

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3 years ago

At the arcade, Sami won 2 blue tickets, 1 yellow ticket, and 3 red tickets for 1500 total points. Jamie won 1 blue ticket, 2 yel

aleksandrvk [35]

Answer:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

Step-by-step explanation:

Given

$b = blue$

$y = yellow$

$r = red$

Required

Represent as a matrix

For Sammy:

$2\ blue + 1\ yellow + 3\ red =1500$

So, we have:

$2b + 1y + 3r = 1500$

$2b + y + 3r = 1500$

For Jamie:

$1\ blue + 2\ yellow + 2\ red =1225$

So, we have:

$1b + 2y + 2r = 1225$

$b + 2y + 2r = 1225$

For Yvonne:

$2\ blue + 3\ yellow + 1\ red =1200$

So, we have:

$2b + 3y + 1r = 1200$

$2b + 3y + r = 1200$

The system of equations are:

$2b + y + 3r = 1500$

$b + 2y + 2r = 1225$

$2b + 3y + r = 1200$

To represent as a matrix, we have:

$\left[\begin{array}{ccc}b_1&y_1&r_1\\b_2&y_2&r_2\\b_3&y_3&r_3\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}Total_1&Total_2&Total_3\end{array}\right]$

This gives:

$\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]$ $\left[\begin{array}{c}b&y&r\end{array}\right]$ $= \left[\begin{array}{c}1500&1225&1200\end{array}\right]$

3 0

3 years ago