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borishaifa [10]
2 years ago
8

The value of x is 6. What is the value of y ?

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
5 0

Answer: y = 4.5

scale factor = 4/3

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What is the least common denominator of 1/5 and 7/10
il63 [147K]

Answer:

2/10 7/10

Step-by-step explanation:

7 0
3 years ago
Help me please i need the correct answer
BaLLatris [955]

Answer:

First one is 25/2

Step-by-step explanation:

12×2+1=25/2

9×4+1=36/4

cross multiply and you get

100/

divide both by 2 and you get 50/4 then you divide both by 2 again and you get 25/2 because you can't reduce it anymore

7 0
2 years ago
What is the most specific name of the three-dimensional shape?
Solnce55 [7]
A triangle? Hope this helps! Can I have brainiest? <3
8 0
3 years ago
237 devided by 8 times 564
Goshia [24]
237÷8×564 = 16708.5..
6 0
3 years ago
I need help please. Thanks!
Karolina [17]

Answer:

A

Step-by-step explanation:

We are given the function f and its derivative, given by:

f^\prime(x)=x^2-a^2=(x-a)(x+a)

Remember that f(x) is decreasing when f'(x) < 0.

And f(x) is increasing when f'(x) > 0.

Firstly, determining our zeros for f'(x), we see that:

0=(x-a)(x+a)\Rightarrow x=a, -a

Since a is a (non-zero) positive constant, -a is negative.

We can create the following number line:

<-----(-a)-----0-----(a)----->

Next, we will test values to the left of -a by using (-a - 1). So:

f^\prime(-a-1)=(-a-1-a)(-a-1+a)=(-2a-1)(-1)=2a+1

Since a is a positive constant, (2a + 1) will be positive as well.

So, since f'(x) > 0 for x < -a, f(x) increases for all x < -a.

To test values between -a and a, we can use 0. Hence:

f^\prime(0)=(0-a)(0+a)=-a^2

This will always be negative.

So, since f'(x) < 0 for -a < x < a, f(x) decreases for all -a < x < a.

Lasting, we can test all values greater than a by using (a + 1). So:

f^\prime(a+1)=(a+1-a)(a+1+a)=(1)(2a+1)=2a+1

Again, since a > 0, (2a + 1) will always be positive.

So, since f'(x) > 0 for x > a, f(x) increases for all x > a.

The answer choices ask for the domain for which f(x) is decreasing.

f(x) is decreasing for -a < x < a since f'(x) < 0 for -a < x < a.

So, the correct answer is A.

3 0
2 years ago
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