I will give the brainiest to correct answer. Help, please
2 answers:
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You need to note first two things.
1. The function f(x) need to be a continuous function on [-3,-1] (indeed f(x) is a polynomial function, is continuous on every real number x)
2. Take the closed interval [-3,-1]
Now, evaluate f(-3) and f(-1).
So, we have f(-3) < 0 and f(-1). So, , then by the Intermediate Value Theorem, there exist
such that
.
Answer with Step-by-step explanation:
The given differential euation is
where
'k' is constant of integration whose value is obtained by the given condition that y(2)=0\\
Thus the solution of the differential becomes