Answer:
do the times first then the plus then minus last
Step-by-step explanation:
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Answer:
Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.
Sounds that you have several answer choices. If that's the case, you need to share those choices. All of them are probably inequalities.
Answer:
t = 1
Step-by-step explanation:
2t + 8 = 10
2t = 2 (-8 on both sides)
t = 1 (divide 2 on both sides)
