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yan [13]
2 years ago
12

9y²+21-18=0pls tell how to do​

Mathematics
1 answer:
alex41 [277]2 years ago
4 0

Hello,

I think it is 9y² + 21y - 18 = 0

we have a = 9 ; b = 21 and c = -18

∆ = b² - 4ac = 21² - 4 × 9 × (-18) = 1089 > 0

x1 = (-b - √∆)/2a = (-21 - 33)/9 = 6

x2 = (-b + √∆)/2a = (-21 + 33)/9 = 12/9 = 4/3

S = {4/3 ; 6}

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What’s the verticals asymptote
Rzqust [24]

Answer:

A vertical asymptote is

Step-by-step explanation:

A vertical asymptote (or VA for short) for a function is a vertical line x = k showing where a function f(x) becomes unbounded. In other words, the y values of the function get arbitrarily large in the positive sense (y→ ∞) or negative sense (y→ -∞) as x approaches k, either from the left or from the right.

3 0
4 years ago
Find the sum of all the two-digit numbers that divide 170 with a remainder of 5.
ss7ja [257]

Answer:

114

Step-by-step explanation:

To find - Find the sum of all the two-digit numbers that divide 170 with a remainder of 5.

Proof -

The 2 digit number is 11

170 = 11(15) + 5

The two digit number is 15

170 = 15(11) + 5

The two digit number is 33

170 = 33(5) + 5

The two digit number is 55

170 = 55(3) + 5

∴ we get

The two digit numbers are

11, 15, 33, 55

Their sum is equals to

11 + 15 + 33 + 55 = 114

3 0
3 years ago
I don't understand how to do this question, I need help<br><br> Find the value of x in each diagram
Korvikt [17]

Answer:

A. x = 8.

B. x = 31.

C. x = 32.

Step-by-step explanation:

Here. the sum of the 2 parallel sides of the trapezoid = 2 * length of the middle line segment.

MN + RS = 2PQ

32+ x = 2*20

x =  40 - 32

x = 8.

MN + RS = 2PQ

20 + 42 = 2PQ

2x =  62

x = 31

MN + RS = 2PQ

22 + 42 = 2PQ

2x =  64

x = 32.

5 0
3 years ago
Write the standard form of the equation of the line that passes through the given points (5,3) and (8,-2)
julsineya [31]

Answer:

y+5/3x=34/3

Step-by-step explanation:

y=mx+b

3=5m+b

-2=8m+b   (system of equations, subtract them)

5=-3m

-5/3=m

3=5m+b

3=5(-5/3)+b

3=-25/3+b

9/3+25/3=b

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y=-5/3x+34/3

y+5/3x=34/3

6 0
4 years ago
Find the Lateral area for the regular pyramid. (Keep it as a Square Root)
Shtirlitz [24]

1. You must apply the following formula: 


 LA=<span>1/2 ×(Perimeter of the base)(Slant length)</span>

<span>
</span>

<span> 2. The slant length is (By </span><span> the Pythagorean Theorem):</span>

<span> a</span><span>^2=b^2+c^2</span>

<span> </span><span>a= b^2+c^2</span>

<span> a</span><span>=</span><span>√(</span><span>1^2+3^2)</span>

<span> </span><span>a=√10</span>

<span>
</span>

<span> 3. </span><span>The p</span><span>erimeter of the base is:</span>

<span>
</span>

<span> </span><span>P=2+2+2+2</span>

<span> </span><span>P=8</span>

<span>
</span>

<span> 4. </span><span>Then, you have:</span>

<span>
</span>

<span> LA=</span><span>1/2 ×(Perimeter of the base)(Slant Length)</span>

<span> LA=</span><span>1/2 ×(8)(</span><span>√</span><span>10)</span>

<span> LA=</span><span>(</span><span>8√10)/2</span>

<span> LA=</span><span>4√10</span>

3 0
3 years ago
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