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Fantom [35]
2 years ago
9

Help as soon as possible thanks

Mathematics
1 answer:
frutty [35]2 years ago
5 0
6x11=66ft
3x14=42ft

Add the answers together
42+66
= 108 squared feet
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Write the number in scientific notation.
EleoNora [17]

Answer:

8.5 x 10 ^4 for 85 000

6.7 x 10 ^-6 for 0.0000067

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3 years ago
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Chris Johnson ran the 40- yard dash in 4.24 seconds. What is the rate of speed? Round any answer to the nearest hundredth
sineoko [7]
Distance divided by time is speed. To find the rate of speed, divide 40 yards by 4.24 seconds which is approximately 9.43 yards per second. 9.43 yards per second is the rate of speed.
5 0
3 years ago
Question Help
lana [24]
B I’m pretty sure I think or 826
4 0
3 years ago
Amelia and Jayden work at a furniture store. Amelia is paid $185 per week plus 9.5% of her total sales in dollars, xx, which can
almond37 [142]

Answer:

The weekly sales must be $12,600

Step-by-step explanation:

if their pay is the same, the equations have to be equal

amelia = jayden

185 +.095x = 311 +.085x

subtract  .085x from each side

185 +.095x-.085x = 311 +.085x-.085x

185+.01x = 311

subtract 185 from each side

185-185+.01x = 311-185

.01x = 126

divide by .01

.01x/.01 = 126/.01

x = 12600

7 0
3 years ago
Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)
JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is \left(\frac{-9}{2}, \frac{-3}{2}\right)

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right) is given by:

\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9

Plugging in the values in formula, we get,

\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}

Hence, the midpoint of the segment is \left(\frac{-9}{2}, \frac{-3}{2}\right)

6 0
3 years ago
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