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e-lub [12.9K]
4 years ago
5

What is the graph of the direct variation equation? Y=5/2x

Mathematics
1 answer:
Aneli [31]4 years ago
6 0

Given equation : y=5/2x.

Solution: In order to graph direct variation equation, we need to make a table of different values of x and y.

We need to plug some values of x's in equation to get values of y's.

Because, we have fraction 5/2, and 2 in denominator. So it would be better to take multiples of 2, so that we don't get values in decimals.

Let us take x=0 first.

Plugging x=0 in given equation, we get

y=5/2x = 5/2(0) = 0.

Let us take x=2 first.

Plugging x=2 in given equation, we get

y=5/2 *(2) = 5

Let us take x=2 first.

Plugging x=4 in given equation, we get

y=5/2 *(4) = 5 *2 = 10.

We got three coordinates for the graph (0,0) , (2,5) and (4, 10).

Let us plot those coordinates on the graph and join the points to draw a straight line.


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what is the difference between dependent variable independent variable vs response variable explanatory variable?
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Step-by-step explanation:

we are to distinguish between

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f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?
Leya [2.2K]

The equivalent expression to \mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}

<h3>What are the equivalent expressions?</h3>

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

  • r(x) = 3x - 1
  • s(x) = 2x + 1

Then the fractional form can be an expression as:

\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}

where;

  • x = 6

\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}

\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}

\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}

Learn more about equivalent expressions here:

brainly.com/question/24734894

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The 25th term of a sequence is 121. The 80th term is 506. What is the first term
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-47

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that's the correct answer

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