You have a 30 out of 37% chance so i would say 53 cents
i hope this helps at least a little
good luck!
The area of the two triangular bases is
(total base area) = 2×(1/2)bh
= bh
= (10 m)(6 m) = 10·6 m² = 60 m²
The area of the three rectangles making up the remaining faces of the prism is
(total lateral area) = length×base + length×height + length×hypotenuse
= length×(base + height + hypotenuse)
= (16 m)(10 m + 6 m + 11.6 m)
= (16 m)(27.6 m) = 16·27.6 m² = 441.6 m²
Then the surface area of the prism is the sum of these
surface area = total base area + total lateral area
= 60 m² + 441.6² = 501.6 m²
When rounded to the nearest whole number, this is
A) 502 m²
Answer:
The lateral height of the square pyramid is 
Step-by-step explanation:
step 1
Find the surface area of the cube
The surface area of the cube is equal to
where
b is the length side of the cube
w have
substitute
step 2
Find the lateral height of the square pyramid
we know that
the surface area of the square pyramid is equal to
where
B is the area of the base
b is the base of the lateral triangle (base of the square)
h is the lateral height of the square pyramid
-----> is the same surface that the cube
substitute the values and solve for h
Answer:
its going to be D (x,y) - (x-2,y-4)
Step-by-step explanation:
Answer:
first blank is 5 2nd blank is 11 and 3rd blank is 14.
Step-by-step explanation:
its plus 3 each so 2+3=5 then you keep on going until you finnish. Please mark me as brainliest
