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geniusboy [140]
3 years ago
10

"5. Multiple-choice questions each have five possible answers (a,b,c,d,e), one of which is correct. Assume that you guess the an

swers to three such questions. a. Use the multiplication rule to find P(WCC), where C denotes a correct answer and W denotes a wrong answer. b. Beginning with WCC, make a complete list of the different possible arrangements of two correct answers and one wrong answer and find the probability of each. c. Based on the results of part (b) what is the probability of getting exactly two correct answers when three guesses are made?"
Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Answer:

A) P(WWC) = 0.128

B) P(WCC) = 0.032

P(CWC) = 0.032

P(CCW) = 0.032

C) probability of getting 2 correct answers when 3 guesses are made is i.e P (1 wrong and 2 correct) = 0.064

Step-by-step explanation:

A) Using the multiplication rule, we have; P(A and B) = P(A) x P(B)

Probability of a wrong answer = 4/5 = 0.8

Probability of a correct answer = 1/5 =0.2

Thus; P(WWC) = 0.8 x 0.8 x 0.2 = 0.128

B) Beginning with one wrong and two correct answers, a complete list of all possibilities is;

P(WCC), P(CWC), P(CCW)

Hence the complete list is;

(0.8 x 0.2 x 0.2); (0.2 x 0.8 x 0.2); (0.2 x 0.2 x 0.8)

So we have;

P(WCC) = 0.032

P(CWC) = 0.032

P(CCW) = 0.032

C) Based on the results above, the probability of getting 2 correct answers when 3 guesses are made is i.e P(1 wrong and 2 correct) = 2 x 0.032 = 0.064

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oksano4ka [1.4K]

Answer:

The answer is option 3.

Step-by-step explanation:

First we have to find the area of both rectangle and triangle :

Rectangle,

area = base \times height

Let base = 9,

Let height = 3,

area = 9 \times 3 \\ area = 27 \:  {m}^{2}

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area =  \frac{1}{2}  \times base \times height

Let base = 3,

Let height = 3,

area =  \frac{1}{2}  \times 3 \times 3 \\ area =  \frac{1}{2}  \times 9 \\ area =  \frac{9}{2}  \\ area = 4.5 \:  {m}^{2}

Lastly, in order to find the shaded region you have to substract the area of triangle from the area of rectangle :

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x = 0

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2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
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Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

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(a)

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Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

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P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

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Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

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