So, we know the center is at -1, -3, hmmm what's the radius anyway?
well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus
![\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ -1 &,& -3~) % (c,d) &&(~ -7 &,& -5~) \end{array} \\\\\\ d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2} \\\\\\ r=\sqrt{36+4}\implies r=\sqrt{40}\\\\ -------------------------------](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%20-1%20%26%2C%26%20-3~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%20-7%20%26%2C%26%20-5~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ar%3D%5Csqrt%7B%5B-7-%28-1%29%5D%5E2%2B%5B-5-%28-3%29%5D%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B%28-7%2B1%29%5E2%2B%28-5%2B3%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ar%3D%5Csqrt%7B36%2B4%7D%5Cimplies%20r%3D%5Csqrt%7B40%7D%5C%5C%5C%5C%0A-------------------------------)
Answer:
12 centimeters
Step-by-step explanation:
An isosceles triangle has two congruent sides which are legs(2 sides having same length )If x is length of each leg, then we ca write the equation like this
equation: x+x+8=32
combine like terms
2x +8 = 32
minus 8 from each side
2x=32-8
2x=24
divide both sides by 2
2x/2 = 24/2
x=12 centimeters
Im pretty sure its b im soo sorry if im wrong.
Answer:
X, process, y
-2, 3(-2), -6
-1, 3(-1), -3
0, 3(0), 0
1, 3(1), 3
2, 3(2), 6
X = -2, -1, 0, 1, 2,
Y = -6, -3, 0, -3, -6
Step-by-step explanation:
Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)
Graph is the image I added onto this.
Solving for Y below:
3(-2)= -6
3(-1)= -3
3(0)= 0
3(1)= 3
3(2)= 6
Hope this helps.
A. the answer is the first one