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ipn [44]
3 years ago
6

Negative 50 over negative 5 integers

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0

10 is the answer

\frac{ - 50}{ - 5}  = 10 \\

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What does 21÷3+(3×9)×9+5 equal? show work below plz
igor_vitrenko [27]
3x9=27
21/3 = 7
so
7+27x9+5
27x9=243
243+7+5
answer is 255
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You earn 35 for washing 7 cars how much do you earn for washing 4 cars
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20

Step-by-step explanation:

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Brett lives 3/10 mile from school. If he rides his bike to and from school each day,Monday to Friday, how many miles does he rid
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Two trips a day for 5 days = 10 trips
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Virginia beach is about 20 miles wide and 28 miles long. if one inch of rain falls there during a daily rain shower, how many cu
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Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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