For this case we define the following variables:
x: Number of party dresses
y: Number of suits
You have 30 hours per week to cut, that is, the first equation is given by:

It is also known that 25 hours per week are available for sewing, that is:

It has a system of two equations with two unknowns, solving we have:

Multiplying the second equation by -1:

Adding up:

Substituting x in the first equation:

Clearing and:


Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.
Answer:
5 Party dresses
5 Suits
9514 1404 393
Answer:
2
Step-by-step explanation:
The products of chord lengths are the same for the intersecting chords:
AQ×BQ = CQ×DQ
6×12 = CQ×(38 -CQ)
This gives a quadratic in CQ:
CQ² -38CQ +72 = 0 . . . . . write in standard form
(CQ -2)(CQ -36) = 0 . . . . . factor the quadratic
CQ = 2 or 36 . . . . . . . values of CQ that make the factors zero
The minimum length of CQ is 2 units. (DQ will be 36.)
The answer is 33. First do 3 times 5, 15, then do that -2. 13. 13 plus 4 times 5 is 33 :)